100p2=4

Solution for 100p2=4 equation:

100p^2=4

We move all terms to the left:

100p^2-(4)=0

a = 100; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·100·(-4)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40}{2*100}=\frac{-40}{200}
=-1/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40}{2*100}=\frac{40}{200}
=1/5
$