2m/5=1/3)2m-12)

Solution for 2m/5=1/3)2m-12) equation:

2m/5=1/3)2m-12)

We move all terms to the left:

2m/5-(1/3)2m-12))=0


Domain of the equation: 3)2m!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

2m/5-(+1/3)2m-12))=0

We add all the numbers together, and all the variables

2m/5-(+1/3)2m=0

We multiply parentheses

-2m^2+2m/5=0

We multiply all the terms by the denominator


-2m^2*5+2m=0

Wy multiply elements

-10m^2+2m=0

a = -10; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-10)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-10}=\frac{-4}{-20}
=1/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-10}=\frac{0}{-20}
=0
$