2(3y+6)-(3y-42)=145

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Solution for 2(3y+6)-(3y-42)=145 equation: 



2(3y+6)-(3y-42)=145

We move all terms to the left:

2(3y+6)-(3y-42)-(145)=0

We multiply parentheses

6y-(3y-42)+12-145=0

We get rid of parentheses

6y-3y+42+12-145=0

We add all the numbers together, and all the variables

3y-91=0

We move all terms containing y to the left, all other terms to the right

3y=91

y=91/3

y=30+1/3

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