2m-5=0/3m+2

Solution for 2m-5=0/3m+2 equation:

2m-5=0/3m+2

We move all terms to the left:

2m-5-(0/3m+2)=0


Domain of the equation: 3m+2)!=0

m∈R


We get rid of parentheses

2m-0/3m-2-5=0

We multiply all the terms by the denominator


2m*3m-2*3m-5*3m-0=0

We add all the numbers together, and all the variables

2m*3m-2*3m-5*3m=0

Wy multiply elements

6m^2-6m-15m=0

We add all the numbers together, and all the variables

6m^2-21m=0

a = 6; b = -21; c = 0;
Δ = b2-4ac
Δ = -212-4·6·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-21}{2*6}=\frac{0}{12}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+21}{2*6}=\frac{42}{12}
=3+1/2
$