3(4x-5)+3x=2(4x-6)+x+9

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Solution for 3(4x-5)+3x=2(4x-6)+x+9 equation: 



3(4x-5)+3x=2(4x-6)+x+9

We move all terms to the left:

3(4x-5)+3x-(2(4x-6)+x+9)=0

We add all the numbers together, and all the variables

3x+3(4x-5)-(2(4x-6)+x+9)=0

We multiply parentheses

3x+12x-(2(4x-6)+x+9)-15=0



We calculate terms in parentheses: -(2(4x-6)+x+9), so:

2(4x-6)+x+9

We add all the numbers together, and all the variables

x+2(4x-6)+9

We multiply parentheses

x+8x-12+9

We add all the numbers together, and all the variables

9x-3

Back to the equation:

-(9x-3)



We add all the numbers together, and all the variables

15x-(9x-3)-15=0

We get rid of parentheses

15x-9x+3-15=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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