2m+3=12(4m+6)

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Solution for 2m+3=12(4m+6) equation: 



2m+3=12(4m+6)

We move all terms to the left:

2m+3-(12(4m+6))=0



We calculate terms in parentheses: -(12(4m+6)), so:

12(4m+6)

We multiply parentheses

48m+72

Back to the equation:

-(48m+72)



We get rid of parentheses

2m-48m-72+3=0

We add all the numbers together, and all the variables

-46m-69=0

We move all terms containing m to the left, all other terms to the right

-46m=69

m=69/-46

m=-1+1/2

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