8(b+3)-6=-4+2(b-4)

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Solution for 8(b+3)-6=-4+2(b-4) equation: 



8(b+3)-6=-4+2(b-4)

We move all terms to the left:

8(b+3)-6-(-4+2(b-4))=0

We multiply parentheses

8b-(-4+2(b-4))+24-6=0



We calculate terms in parentheses: -(-4+2(b-4)), so:

-4+2(b-4)

determiningTheFunctionDomain
2(b-4)-4

We multiply parentheses

2b-8-4

We add all the numbers together, and all the variables

2b-12

Back to the equation:

-(2b-12)



We add all the numbers together, and all the variables

8b-(2b-12)+18=0

We get rid of parentheses

8b-2b+12+18=0

We add all the numbers together, and all the variables

6b+30=0

We move all terms containing b to the left, all other terms to the right

6b=-30

b=-30/6

b=-5

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