2m+1/6=6(1/3m+1)

Solution for 2m+1/6=6(1/3m+1) equation:

2m+1/6=6(1/3m+1)

We move all terms to the left:

2m+1/6-(6(1/3m+1))=0


Domain of the equation: 3m+1))!=0

m∈R


We calculate fractions


2m+()/3m+3m/3m=0

Fractions to decimals

()/3m+2m+1=0

We multiply all the terms by the denominator


2m*3m+1*3m+()=0

We add all the numbers together, and all the variables

2m*3m+1*3m=0

Wy multiply elements

6m^2+3m=0

a = 6; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·6·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*6}=\frac{-6}{12}
=-1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*6}=\frac{0}{12}
=0
$