30(e+10)-290=5(6e+2)

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Solution for 30(e+10)-290=5(6e+2) equation: 



30(e+10)-290=5(6e+2)

We move all terms to the left:

30(e+10)-290-(5(6e+2))=0

We multiply parentheses

30e-(5(6e+2))+300-290=0



We calculate terms in parentheses: -(5(6e+2)), so:

5(6e+2)

We multiply parentheses

30e+10

Back to the equation:

-(30e+10)



We add all the numbers together, and all the variables

30e-(30e+10)+10=0

We get rid of parentheses

30e-30e-10+10=0

We add all the numbers together, and all the variables

=0

e=0/1

e=0

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