2k/3=(k-1)/5

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Solution for 2k/3=(k-1)/5 equation: 



2k/3=(k-1)/5

We move all terms to the left:

2k/3-((k-1)/5)=0

We calculate fractions


10k^2/()+(-((k-1)*3)/()=0



We calculate terms in parentheses: +(-((k-1)*3)/(), so:

-((k-1)*3)/(

We multiply all the terms by the denominator


-((k-1)*3)



We calculate terms in parentheses: -((k-1)*3), so:

(k-1)*3

We multiply parentheses

3k-3

Back to the equation:

-(3k-3)



We get rid of parentheses

-3k+3

Back to the equation:

+(-3k+3)



We get rid of parentheses

10k^2/()-3k+3=0

We multiply all the terms by the denominator


10k^2-3k*()+3*()=0

We add all the numbers together, and all the variables

10k^2-3k*()=0

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