(7/2)+(1/2)x=3x+(5/2)x

Solution for (7/2)+(1/2)x=3x+(5/2)x equation:

(7/2)+(1/2)x=3x+(5/2)x

We move all terms to the left:

(7/2)+(1/2)x-(3x+(5/2)x)=0


Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 2)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)x-(3x+(+5/2)x)+(+7/2)=0

We multiply parentheses

x^2-(3x+(+5/2)x)+(+7/2)=0

We get rid of parentheses

x^2-(3x+(+5/2)x)+7/2=0

We calculate fractions


x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$