2k-1=-5-8(k+2)

Solution for 2k-1=-5-8(k+2) equation:

2k-1=-5-8(k+2)

We move all terms to the left:

2k-1-(-5-8(k+2))=0


We calculate terms in parentheses: -(-5-8(k+2)), so:

-5-8(k+2)

determiningTheFunctionDomain
-8(k+2)-5

We multiply parentheses

-8k-16-5

We add all the numbers together, and all the variables

-8k-21

Back to the equation:

-(-8k-21)


We get rid of parentheses

2k+8k+21-1=0

We add all the numbers together, and all the variables

10k+20=0

We move all terms containing k to the left, all other terms to the right

10k=-20

k=-20/10

k=-2