5b2+11b+6=0

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Solution for 5b2+11b+6=0 equation: 



5b^2+11b+6=0

a = 5; b = 11; c = +6;
Δ = b2-4ac
Δ = 112-4·5·6
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$


$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-1}{2*5}=\frac{-12}{10}
=-1+1/5
$


$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+1}{2*5}=\frac{-10}{10}
=-1
$

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