2k+3(2-2k)=5(k-6)

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Solution for 2k+3(2-2k)=5(k-6) equation: 



2k+3(2-2k)=5(k-6)

We move all terms to the left:

2k+3(2-2k)-(5(k-6))=0

We add all the numbers together, and all the variables

2k+3(-2k+2)-(5(k-6))=0

We multiply parentheses

2k-6k-(5(k-6))+6=0



We calculate terms in parentheses: -(5(k-6)), so:

5(k-6)

We multiply parentheses

5k-30

Back to the equation:

-(5k-30)



We add all the numbers together, and all the variables

-4k-(5k-30)+6=0

We get rid of parentheses

-4k-5k+30+6=0

We add all the numbers together, and all the variables

-9k+36=0

We move all terms containing k to the left, all other terms to the right

-9k=-36

k=-36/-9

k=+4

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