2i+1=8(i+2)-5i

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Solution for 2i+1=8(i+2)-5i equation: 



2i+1=8(i+2)-5i

We move all terms to the left:

2i+1-(8(i+2)-5i)=0



We calculate terms in parentheses: -(8(i+2)-5i), so:

8(i+2)-5i

We add all the numbers together, and all the variables

-5i+8(i+2)

We multiply parentheses

-5i+8i+16

We add all the numbers together, and all the variables

3i+16

Back to the equation:

-(3i+16)



We get rid of parentheses

2i-3i-16+1=0

We add all the numbers together, and all the variables

-1i-15=0

We move all terms containing i to the left, all other terms to the right

-i=15

i=15/-1

i=-15

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