4(2x-3)=12(x-3)+18

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Solution for 4(2x-3)=12(x-3)+18 equation: 



4(2x-3)=12(x-3)+18

We move all terms to the left:

4(2x-3)-(12(x-3)+18)=0

We multiply parentheses

8x-(12(x-3)+18)-12=0



We calculate terms in parentheses: -(12(x-3)+18), so:

12(x-3)+18

We multiply parentheses

12x-36+18

We add all the numbers together, and all the variables

12x-18

Back to the equation:

-(12x-18)



We get rid of parentheses

8x-12x+18-12=0

We add all the numbers together, and all the variables

-4x+6=0

We move all terms containing x to the left, all other terms to the right

-4x=-6

x=-6/-4

x=1+1/2

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