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2f+3=2(f+3)
We move all terms to the left:
2f+3-(2(f+3))=0
We calculate terms in parentheses: -(2(f+3)), so:We get rid of parentheses
2(f+3)
We multiply parentheses
2f+6
Back to the equation:
-(2f+6)
2f-2f-6+3=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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