5(3a-4)=(6a+3)-11

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Solution for 5(3a-4)=(6a+3)-11 equation: 



5(3a-4)=(6a+3)-11

We move all terms to the left:

5(3a-4)-((6a+3)-11)=0

We multiply parentheses

15a-((6a+3)-11)-20=0



We calculate terms in parentheses: -((6a+3)-11), so:

(6a+3)-11

We get rid of parentheses

6a+3-11

We add all the numbers together, and all the variables

6a-8

Back to the equation:

-(6a-8)



We get rid of parentheses

15a-6a+8-20=0

We add all the numbers together, and all the variables

9a-12=0

We move all terms containing a to the left, all other terms to the right

9a=12

a=12/9

a=1+1/3

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