2d+(8-5)=10(3)+d(2)

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Solution for 2d+(8-5)=10(3)+d(2) equation: 



2d+(8-5)=10(3)+d(2)

We move all terms to the left:

2d+(8-5)-(10(3)+d(2))=0

We add all the numbers together, and all the variables

-(+d^2+103)+2d+3=0

We get rid of parentheses

-d^2+2d-103+3=0

We add all the numbers together, and all the variables

-1d^2+2d-100=0

a = -1; b = 2; c = -100;
Δ = b2-4ac
Δ = 22-4·(-1)·(-100)
Δ = -396
Delta is less than zero, so there is no solution for the equation

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