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9(5y-9)=3(10y-1)
We move all terms to the left:
9(5y-9)-(3(10y-1))=0
We multiply parentheses
45y-(3(10y-1))-81=0
We calculate terms in parentheses: -(3(10y-1)), so:We get rid of parentheses
3(10y-1)
We multiply parentheses
30y-3
Back to the equation:
-(30y-3)
45y-30y+3-81=0
We add all the numbers together, and all the variables
15y-78=0
We move all terms containing y to the left, all other terms to the right
15y=78
y=78/15
y=5+1/5
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