2c-3=2(6-c)=7c

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Solution for 2c-3=2(6-c)=7c equation: 



2c-3=2(6-c)=7c

We move all terms to the left:

2c-3-(2(6-c))=0

We add all the numbers together, and all the variables

2c-(2(-1c+6))-3=0



We calculate terms in parentheses: -(2(-1c+6)), so:

2(-1c+6)

We multiply parentheses

-2c+12

Back to the equation:

-(-2c+12)



We get rid of parentheses

2c+2c-12-3=0

We add all the numbers together, and all the variables

4c-15=0

We move all terms containing c to the left, all other terms to the right

4c=15

c=15/4

c=3+3/4

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