5(m+4)=(2m+20)

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Solution for 5(m+4)=(2m+20) equation: 



5(m+4)=(2m+20)

We move all terms to the left:

5(m+4)-((2m+20))=0

We multiply parentheses

5m-((2m+20))+20=0



We calculate terms in parentheses: -((2m+20)), so:

(2m+20)

We get rid of parentheses

2m+20

Back to the equation:

-(2m+20)



We get rid of parentheses

5m-2m-20+20=0

We add all the numbers together, and all the variables

3m=0

m=0/3

m=0

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