2c-3=2(6-c)+c

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Solution for 2c-3=2(6-c)+c equation: 



2c-3=2(6-c)+c

We move all terms to the left:

2c-3-(2(6-c)+c)=0

We add all the numbers together, and all the variables

2c-(2(-1c+6)+c)-3=0



We calculate terms in parentheses: -(2(-1c+6)+c), so:

2(-1c+6)+c

We add all the numbers together, and all the variables

c+2(-1c+6)

We multiply parentheses

c-2c+12

We add all the numbers together, and all the variables

-1c+12

Back to the equation:

-(-1c+12)



We get rid of parentheses

2c+1c-12-3=0

We add all the numbers together, and all the variables

3c-15=0

We move all terms containing c to the left, all other terms to the right

3c=15

c=15/3

c=5

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