(n+1)+(n+3)-7-2=5

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Solution for (n+1)+(n+3)-7-2=5 equation: 



(n+1)+(n+3)-7-2=5

We move all terms to the left:

(n+1)+(n+3)-7-2-(5)=0

We add all the numbers together, and all the variables

(n+1)+(n+3)-14=0

We get rid of parentheses

n+n+1+3-14=0

We add all the numbers together, and all the variables

2n-10=0

We move all terms containing n to the left, all other terms to the right

2n=10

n=10/2

n=5

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