2c+150=4(c-230)

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Solution for 2c+150=4(c-230) equation: 



2c+150=4(c-230)

We move all terms to the left:

2c+150-(4(c-230))=0



We calculate terms in parentheses: -(4(c-230)), so:

4(c-230)

We multiply parentheses

4c-920

Back to the equation:

-(4c-920)



We get rid of parentheses

2c-4c+920+150=0

We add all the numbers together, and all the variables

-2c+1070=0

We move all terms containing c to the left, all other terms to the right

-2c=-1070

c=-1070/-2

c=+535

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