2b-7/4+b=3(b+1)-1/10

Solution for 2b-7/4+b=3(b+1)-1/10 equation:

2b-7/4+b=3(b+1)-1/10

We move all terms to the left:

2b-7/4+b-(3(b+1)-1/10)=0

We add all the numbers together, and all the variables

3b-(3(b+1)-1/10)-7/4=0

We calculate fractions


3b+(-(3(b+1)-1*4)/()+()/()=0


We calculate terms in parentheses: +(-(3(b+1)-1*4)/()+()/(), so:

-(3(b+1)-1*4)/()+()/(

We add all the numbers together, and all the variables

-(3(b+1)-1*4)/()+1

We multiply all the terms by the denominator


-(3(b+1)-1*4)+1*()


We calculate terms in parentheses: -(3(b+1)-1*4), so:

3(b+1)-1*4

We add all the numbers together, and all the variables

3(b+1)-4

We multiply parentheses

3b+3-4

We add all the numbers together, and all the variables

3b-1

Back to the equation:

-(3b-1)


We add all the numbers together, and all the variables

-(3b-1)

We get rid of parentheses

-3b+1

Back to the equation:

+(-3b+1)


We get rid of parentheses

3b-3b+1=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation