2(6-2x)+3x=4+(5+x)

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Solution for 2(6-2x)+3x=4+(5+x) equation: 



2(6-2x)+3x=4+(5+x)

We move all terms to the left:

2(6-2x)+3x-(4+(5+x))=0

We add all the numbers together, and all the variables

2(-2x+6)+3x-(4+(x+5))=0

We add all the numbers together, and all the variables

3x+2(-2x+6)-(4+(x+5))=0

We multiply parentheses

3x-4x-(4+(x+5))+12=0



We calculate terms in parentheses: -(4+(x+5)), so:

4+(x+5)

determiningTheFunctionDomain
(x+5)+4

We get rid of parentheses

x+5+4

We add all the numbers together, and all the variables

x+9

Back to the equation:

-(x+9)



We add all the numbers together, and all the variables

-1x-(x+9)+12=0

We get rid of parentheses

-1x-x-9+12=0

We add all the numbers together, and all the variables

-2x+3=0

We move all terms containing x to the left, all other terms to the right

-2x=-3

x=-3/-2

x=1+1/2

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