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4x-13=2x(x-3)
We move all terms to the left:
4x-13-(2x(x-3))=0
We calculate terms in parentheses: -(2x(x-3)), so:We get rid of parentheses
2x(x-3)
We multiply parentheses
2x^2-6x
Back to the equation:
-(2x^2-6x)
-2x^2+4x+6x-13=0
We add all the numbers together, and all the variables
-2x^2+10x-13=0
a = -2; b = 10; c = -13;
Δ = b2-4ac
Δ = 102-4·(-2)·(-13)
Δ = -4
Delta is less than zero, so there is no solution for the equation
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