2b+8-5b+3=(-13)+8b-5

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Solution for 2b+8-5b+3=(-13)+8b-5 equation: 



2b+8-5b+3=(-13)+8b-5

We move all terms to the left:

2b+8-5b+3-((-13)+8b-5)=0

We add all the numbers together, and all the variables

-3b-((-13)+8b-5)+11=0



We calculate terms in parentheses: -((-13)+8b-5), so:

(-13)+8b-5

determiningTheFunctionDomain
8b-5+(-13)

We add all the numbers together, and all the variables

8b-18

Back to the equation:

-(8b-18)



We get rid of parentheses

-3b-8b+18+11=0

We add all the numbers together, and all the variables

-11b+29=0

We move all terms containing b to the left, all other terms to the right

-11b=-29

b=-29/-11

b=2+7/11

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