(2-v)(3v+7)=0

Solution for (2-v)(3v+7)=0 equation:

(2-v)(3v+7)=0

We add all the numbers together, and all the variables

(-1v+2)(3v+7)=0

We multiply parentheses ..

(-3v^2-7v+6v+14)=0

We get rid of parentheses

-3v^2-7v+6v+14=0

We add all the numbers together, and all the variables

-3v^2-1v+14=0

a = -3; b = -1; c = +14;
Δ = b2-4ac
Δ = -12-4·(-3)·14
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-13}{2*-3}=\frac{-12}{-6}
=+2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+13}{2*-3}=\frac{14}{-6}
=-2+1/3
$