2b+3(b-4)=6b+16

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Solution for 2b+3(b-4)=6b+16 equation: 



2b+3(b-4)=6b+16

We move all terms to the left:

2b+3(b-4)-(6b+16)=0

We multiply parentheses

2b+3b-(6b+16)-12=0

We get rid of parentheses

2b+3b-6b-16-12=0

We add all the numbers together, and all the variables

-1b-28=0

We move all terms containing b to the left, all other terms to the right

-b=28

b=28/-1

b=-28

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