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X-1-(5X+4)=3-4(X+2)
We move all terms to the left:
X-1-(5X+4)-(3-4(X+2))=0
We get rid of parentheses
X-5X-(3-4(X+2))-4-1=0
We calculate terms in parentheses: -(3-4(X+2)), so:We add all the numbers together, and all the variables
3-4(X+2)
determiningTheFunctionDomain -4(X+2)+3
We multiply parentheses
-4X-8+3
We add all the numbers together, and all the variables
-4X-5
Back to the equation:
-(-4X-5)
-4X-(-4X-5)-5=0
We get rid of parentheses
-4X+4X+5-5=0
We add all the numbers together, and all the variables
=0
X=0/1
X=0
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