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2a+3=1/2a
We move all terms to the left:
2a+3-(1/2a)=0
Domain of the equation: 2a)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
2a-(+1/2a)+3=0
We get rid of parentheses
2a-1/2a+3=0
We multiply all the terms by the denominator
2a*2a+3*2a-1=0
Wy multiply elements
4a^2+6a-1=0
a = 4; b = 6; c = -1;
Δ = b2-4ac
Δ = 62-4·4·(-1)
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{13}}{2*4}=\frac{-6-2\sqrt{13}}{8} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{13}}{2*4}=\frac{-6+2\sqrt{13}}{8} $
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