32(x-10)+29x+3(x-5)=945

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Solution for 32(x-10)+29x+3(x-5)=945 equation: 



32(x-10)+29x+3(x-5)=945

We move all terms to the left:

32(x-10)+29x+3(x-5)-(945)=0

We add all the numbers together, and all the variables

29x+32(x-10)+3(x-5)-945=0

We multiply parentheses

29x+32x+3x-320-15-945=0

We add all the numbers together, and all the variables

64x-1280=0

We move all terms containing x to the left, all other terms to the right

64x=1280

x=1280/64

x=20

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