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2a(a+3)+5a+5=(a+5)(2a+1)
We move all terms to the left:
2a(a+3)+5a+5-((a+5)(2a+1))=0
We add all the numbers together, and all the variables
5a+2a(a+3)-((a+5)(2a+1))+5=0
We multiply parentheses
2a^2+5a+6a-((a+5)(2a+1))+5=0
We multiply parentheses ..
2a^2-((+2a^2+a+10a+5))+5a+6a+5=0
We calculate terms in parentheses: -((+2a^2+a+10a+5)), so:We add all the numbers together, and all the variables
(+2a^2+a+10a+5)
We get rid of parentheses
2a^2+a+10a+5
We add all the numbers together, and all the variables
2a^2+11a+5
Back to the equation:
-(2a^2+11a+5)
2a^2+11a-(2a^2+11a+5)+5=0
We get rid of parentheses
2a^2-2a^2+11a-11a-5+5=0
We add all the numbers together, and all the variables
=0
a=0/1
a=0
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