(a+3)(a-1)-(a-3)(a+2)=15

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Solution for (a+3)(a-1)-(a-3)(a+2)=15 equation:



(a+3)(a-1)-(a-3)(a+2)=15
We move all terms to the left:
(a+3)(a-1)-(a-3)(a+2)-(15)=0
We multiply parentheses ..
(+a^2-1a+3a-3)-(a-3)(a+2)-15=0
We get rid of parentheses
a^2-1a+3a-(a-3)(a+2)-3-15=0
We multiply parentheses ..
a^2-(+a^2+2a-3a-6)-1a+3a-3-15=0
We add all the numbers together, and all the variables
a^2-(+a^2+2a-3a-6)+2a-18=0
We get rid of parentheses
a^2-a^2-2a+3a+2a+6-18=0
We add all the numbers together, and all the variables
3a-12=0
We move all terms containing a to the left, all other terms to the right
3a=12
a=12/3
a=4

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