2a(3a+5)=a(6a-9)

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Solution for 2a(3a+5)=a(6a-9) equation: 



2a(3a+5)=a(6a-9)

We move all terms to the left:

2a(3a+5)-(a(6a-9))=0

We multiply parentheses

6a^2+10a-(a(6a-9))=0



We calculate terms in parentheses: -(a(6a-9)), so:

a(6a-9)

We multiply parentheses

6a^2-9a

Back to the equation:

-(6a^2-9a)



We get rid of parentheses

6a^2-6a^2+10a+9a=0

We add all the numbers together, and all the variables

19a=0

a=0/19

a=0

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