45-t2=0

Solution for 45-t2=0 equation:

45-t2=0

We add all the numbers together, and all the variables

-1t^2+45=0

a = -1; b = 0; c = +45;
Δ = b2-4ac
Δ = 02-4·(-1)·45
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{5}}{2*-1}=\frac{0-6\sqrt{5}}{-2}
=-\frac{6\sqrt{5}}{-2}
=-\frac{3\sqrt{5}}{-1}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{5}}{2*-1}=\frac{0+6\sqrt{5}}{-2}
=\frac{6\sqrt{5}}{-2}
=\frac{3\sqrt{5}}{-1}
$