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2=Y2-6Y+5
We move all terms to the left:
2-(Y2-6Y+5)=0
We add all the numbers together, and all the variables
-(+Y^2-6Y+5)+2=0
We get rid of parentheses
-Y^2+6Y-5+2=0
We add all the numbers together, and all the variables
-1Y^2+6Y-3=0
a = -1; b = 6; c = -3;
Δ = b2-4ac
Δ = 62-4·(-1)·(-3)
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{6}}{2*-1}=\frac{-6-2\sqrt{6}}{-2} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{6}}{2*-1}=\frac{-6+2\sqrt{6}}{-2} $
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