If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/3x-3/4+5/6x=-2
We move all terms to the left:
1/3x-3/4+5/6x-(-2)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
1/3x+5/6x+2-3/4=0
We calculate fractions
(-324x^2)/288x^2+96x/288x^2+240x/288x^2+2=0
We multiply all the terms by the denominator
(-324x^2)+96x+240x+2*288x^2=0
We add all the numbers together, and all the variables
(-324x^2)+336x+2*288x^2=0
Wy multiply elements
(-324x^2)+576x^2+336x=0
We get rid of parentheses
-324x^2+576x^2+336x=0
We add all the numbers together, and all the variables
252x^2+336x=0
a = 252; b = 336; c = 0;
Δ = b2-4ac
Δ = 3362-4·252·0
Δ = 112896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{112896}=336$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(336)-336}{2*252}=\frac{-672}{504} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(336)+336}{2*252}=\frac{0}{504} =0 $
| e/3-7=15 | | -2(6x+10)+10=-34 | | 7|-4x-1|=49 | | -2(6x+10=-34 | | 9n-29=3n+7 | | 7(3x-10)=-49 | | -4x^2+20x+49=0 | | 6x+25=64 | | r/2+9=30 | | (-2(-7x+5))-7=40-5x | | 11x+2=5x+21 | | 3u-15=21 | | -1/4(x+2)-5=x | | 4w+8=40 | | 117-w=161 | | -1/4(x+2)=5=x | | 210=51-x | | 178-y=234 | | 123-y=207 | | (4x-1)^2=(2x+1)^2 | | 155=21-x | | 7x-20=2x+15 | | 6+31=8t-14 | | 2x+23+3x=57 | | 1/(1-0.95x)=2 | | 13p+15=-11 | | 3m/5=-18 | | 3÷5x=9 5+x=-4 | | 8x+8=12x-4 | | -8z=120-2z | | 10+3y-5=2y+2-y | | 5+x=-4 |