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2=5xx3(x+1)
We move all terms to the left:
2-(5xx3(x+1))=0
We calculate terms in parentheses: -(5xx3(x+1)), so:We get rid of parentheses
5xx3(x+1)
We multiply parentheses
5x^2+5x
Back to the equation:
-(5x^2+5x)
-5x^2-5x+2=0
a = -5; b = -5; c = +2;
Δ = b2-4ac
Δ = -52-4·(-5)·2
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{65}}{2*-5}=\frac{5-\sqrt{65}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{65}}{2*-5}=\frac{5+\sqrt{65}}{-10} $
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