x2+20=x2+4x+4

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Solution for x2+20=x2+4x+4 equation: 



x2+20=x2+4x+4

We move all terms to the left:

x2+20-(x2+4x+4)=0

We add all the numbers together, and all the variables

-(+x^2+4x+4)+x2+20=0

We add all the numbers together, and all the variables

x^2-(+x^2+4x+4)+20=0

We get rid of parentheses

x^2-x^2-4x-4+20=0

We add all the numbers together, and all the variables

-4x+16=0

We move all terms containing x to the left, all other terms to the right

-4x=-16

x=-16/-4

x=+4

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