2=5(52-z)-9(32-2)

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Solution for 2=5(52-z)-9(32-2) equation: 



2=5(52-z)-9(32-2)

We move all terms to the left:

2-(5(52-z)-9(32-2))=0

We add all the numbers together, and all the variables

-(5(-1z+52)-930)+2=0



We calculate terms in parentheses: -(5(-1z+52)-930), so:

5(-1z+52)-930

We multiply parentheses

-5z+260-930

We add all the numbers together, and all the variables

-5z-670

Back to the equation:

-(-5z-670)



We get rid of parentheses

5z+670+2=0

We add all the numbers together, and all the variables

5z+672=0

We move all terms containing z to the left, all other terms to the right

5z=-672

z=-672/5

z=-134+2/5

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