(x+4)-2(4-5x)=5(x+3)-1

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Solution for (x+4)-2(4-5x)=5(x+3)-1 equation: 



(x+4)-2(4-5x)=5(x+3)-1

We move all terms to the left:

(x+4)-2(4-5x)-(5(x+3)-1)=0

We add all the numbers together, and all the variables

(x+4)-2(-5x+4)-(5(x+3)-1)=0

We multiply parentheses

(x+4)+10x-(5(x+3)-1)-8=0

We get rid of parentheses

x+10x-(5(x+3)-1)+4-8=0



We calculate terms in parentheses: -(5(x+3)-1), so:

5(x+3)-1

We multiply parentheses

5x+15-1

We add all the numbers together, and all the variables

5x+14

Back to the equation:

-(5x+14)



We add all the numbers together, and all the variables

11x-(5x+14)-4=0

We get rid of parentheses

11x-5x-14-4=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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