2=4(2a-3)-(7a+4)=

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Solution for 2=4(2a-3)-(7a+4)= equation: 



2=4(2a-3)-(7a+4)=

We move all terms to the left:

2-(4(2a-3)-(7a+4))=0



We calculate terms in parentheses: -(4(2a-3)-(7a+4)), so:

4(2a-3)-(7a+4)

We multiply parentheses

8a-(7a+4)-12

We get rid of parentheses

8a-7a-4-12

We add all the numbers together, and all the variables

a-16

Back to the equation:

-(a-16)



We get rid of parentheses

-a+16+2=0

We add all the numbers together, and all the variables

-1a+18=0

We move all terms containing a to the left, all other terms to the right

-a=-18

a=-18/-1

a=+18

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