-3(-6u+4)-3u=3(u-7)-6

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Solution for -3(-6u+4)-3u=3(u-7)-6 equation: 



-3(-6u+4)-3u=3(u-7)-6

We move all terms to the left:

-3(-6u+4)-3u-(3(u-7)-6)=0

We add all the numbers together, and all the variables

-3u-3(-6u+4)-(3(u-7)-6)=0

We multiply parentheses

-3u+18u-(3(u-7)-6)-12=0



We calculate terms in parentheses: -(3(u-7)-6), so:

3(u-7)-6

We multiply parentheses

3u-21-6

We add all the numbers together, and all the variables

3u-27

Back to the equation:

-(3u-27)



We add all the numbers together, and all the variables

15u-(3u-27)-12=0

We get rid of parentheses

15u-3u+27-12=0

We add all the numbers together, and all the variables

12u+15=0

We move all terms containing u to the left, all other terms to the right

12u=-15

u=-15/12

u=-1+1/4

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