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2=3/5*2+b
We move all terms to the left:
2-(3/5*2+b)=0
Domain of the equation: 5*2+b)!=0We add all the numbers together, and all the variables
b∈R
-(+b+3/5*2)+2=0
We get rid of parentheses
-b+2-3/5*2=0
We multiply all the terms by the denominator
-b*5*2-3+2*5*2=0
We add all the numbers together, and all the variables
-b*5*2+17=0
Wy multiply elements
-10b*2+17=0
Wy multiply elements
-20b+17=0
We move all terms containing b to the left, all other terms to the right
-20b=-17
b=-17/-20
b=17/20
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