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1=3/5(1)+b
We move all terms to the left:
1-(3/5(1)+b)=0
Domain of the equation: 51+b)!=0We add all the numbers together, and all the variables
We move all terms containing b to the left, all other terms to the right
b)!=-51
b!=-51/1
b!=-51
b∈R
-(+b+3/51)+1=0
We get rid of parentheses
-b+1-3/51=0
We multiply all the terms by the denominator
-b*51-3+1*51=0
We add all the numbers together, and all the variables
-b*51+48=0
Wy multiply elements
-51b+48=0
We move all terms containing b to the left, all other terms to the right
-51b=-48
b=-48/-51
b=16/17
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