2=11+3(m+3)m=

Solution for 2=11+3(m+3)m= equation:

2=11+3(m+3)m=

We move all terms to the left:

2-(11+3(m+3)m)=0


We calculate terms in parentheses: -(11+3(m+3)m), so:

11+3(m+3)m

determiningTheFunctionDomain
3(m+3)m+11

We multiply parentheses

3m^2+9m+11

Back to the equation:

-(3m^2+9m+11)


We get rid of parentheses

-3m^2-9m-11+2=0

We add all the numbers together, and all the variables

-3m^2-9m-9=0

a = -3; b = -9; c = -9;
Δ = b2-4ac
Δ = -92-4·(-3)·(-9)
Δ = -27
Delta is less than zero, so there is no solution for the equation