2=-(4+m)+2

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Solution for 2=-(4+m)+2 equation: 



2=-(4+m)+2

We move all terms to the left:

2-(-(4+m)+2)=0

We add all the numbers together, and all the variables

-(-(m+4)+2)+2=0



We calculate terms in parentheses: -(-(m+4)+2), so:

-(m+4)+2

We get rid of parentheses

-m-4+2

We add all the numbers together, and all the variables

-1m-2

Back to the equation:

-(-1m-2)



We get rid of parentheses

1m+2+2=0

We add all the numbers together, and all the variables

m+4=0

We move all terms containing m to the left, all other terms to the right

m=-4

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